Hóa học Lớp 11: Hoà tan hoàn toàn 2,32 gam hổn hợp FeO và Fe2O3 vào dung dịch HNO3 đặc, dư thì thu được 0,224 lít khí NO2 (sản phẩm khử duy nhất, ở đk

Question

Hóa học Lớp 11:  Hoà tan hoàn toàn 2,32 gam hổn hợp FeO và Fe2­O3 vào dung dịch HNO3 đặc, dư thì thu được 0,224 lít khí NO2 (sản phẩm khử duy nhất, ở đktc). Khối lượng muối Fe(NO3)3 thu được là, giúp em giải bài này ạ, em cảm ơn thầy cô và các bạn nhiều.

thucquyenlan · Answer

Q  u  y  &#160;  &#273;  &#7893;  i  :  &#160;      F  e  :  &#160;  x  &#160;  m  o  l      O  :  y  &#160;  m  o  l        =  &#62;  56  x  +  16  y  =  2  ,  32  &#160;  (  1  )    n  N   O  2   =  0  ,  01  &#160;  m  o  l    F  e  &#160;  &#160;  &#160;  -  3  e  -  &#62;  F   e   3  +    &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;   N   +  5    &#160;  &#160;  &#160;  &#160;  +  1  e  -  -  -  &#62;   N   +  4      x  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  3  x  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  0  ,  01  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  0  ,  01    &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;   O  0   &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  +  2  e  -  -  -  &#62;   O   2  -      &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  2  y  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  &#160;  y    T  h  e  o  &#160;  B  T  e  &#160;  t  a  &#160;  c  &#243;  :  &#160;  3  x  =  0  ,  01  +  2  y  &#160;  (  2  )       Từ (1)(2)=>x=0,03 và y=0,04     =  &#62;   m   F  e     N   O  3     3     =  0  ,  03  .  242  =  7  ,  26  g     Vậy: 7,26g

Hóa học Lớp 11: Hoà tan hoàn toàn 2,32 gam hổn hợp FeO và Fe2­O3 vào dung dịch HNO3 đặc, dư thì thu được 0,224 lít khí NO2 (sản phẩm khử duy nhất, ở đk

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Hóa học Lớp 11: Hoà tan hoàn toàn 2,32 gam hổn hợp FeO và Fe2O3 vào dung dịch HNO3 đặc, dư thì thu được 0,224 lít khí NO2 (sản phẩm khử duy nhất, ở đk